Edit: This only refers to costs (paid by the manufacturers), not fees (paid for by the buyers).

  • ulterno@programming.dev
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    6 hours ago

    Considering that
    Power = WorkDone / TimeTaken
    and lets just say for this instance that WorkDone is same for the jet and for the teleporter[1], which is kinda wrong, but won’t matter anyway as you see further.

    Then,
    Powerteleporter = Powerjet × TimeTakenjet / TimeTakenteleporter

    then going with “instantaneous”

    With limit(TimeTakenteleporter ⟶ 0)

    Powerteleporter ⟶ ∞

    Now, someone will ask, what if WorkDone in case of teleportation is actually close to 0.
    But that won’t happen, simply because the minimum value for WorkDone in that case would be equivalent to the change in gravitational potential, making it a significant amount as compared to the other limits.


    Oh and digital goods do have an energy cost, btw.


    1. because calculating work done in such a scenario is kinda hard ↩︎